(x-3)^1/3-(x-3)^2/3

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Solution for (x-3)^1/3-(x-3)^2/3 equation: 


x in (-oo:+oo)

((x-3)^1)/3-(((x-3)^2)/3) = 0

(x-3)/3-(((x-3)^2)/3) = 0

(x-3)/3+(-1*(x-3)^2)/3 = 0

x-1*(x-3)^2-3 = 0

7*x-x^2-12 = 0

7*x-x^2-12 = 0

7*x-x^2-12 = 0

DELTA = 7^2-(-12*(-1)*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)-7)/(-1*2) or x = (-1^(1/2)-7)/(-1*2)

x = 3 or x = 4

(x-3)*(x-4) = 0

((x-3)*(x-4))/3 = 0

((x-3)*(x-4))/3 = 0 // * 3

(x-3)*(x-4) = 0

( x-3 )

x-3 = 0 // + 3

x = 3

( x-4 )

x-4 = 0 // + 4

x = 4

x in { 3, 4 }

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